11b^2-25b-4=-6b+6b^2

Solution for 11b^2-25b-4=-6b+6b^2 equation:

11b^2-25b-4=-6b+6b^2

We move all terms to the left:

11b^2-25b-4-(-6b+6b^2)=0

We get rid of parentheses

11b^2-6b^2+6b-25b-4=0

We add all the numbers together, and all the variables

5b^2-19b-4=0

a = 5; b = -19; c = -4;
Δ = b2-4ac
Δ = -192-4·5·(-4)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-21}{2*5}=\frac{-2}{10}
=-1/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+21}{2*5}=\frac{40}{10}
=4
$